Need help understanding duty cycle

[2x0]

At 6300rpm I am at 13.77ms injector pulse and 72% duty cycle at full boost.

Is there an equation to figure out maximum pulse at 8000rpm, or better yet what my estimated duty cycle at 8000rpm would be assuming the same pulse width?

I know there is a relation between injector ms and rpm, just want to make sure I am doing it right so I don't run out of injector during a pull.

Thanks,

[Hondata]

duty cycle = injector duration * rpm / 1200

So if your pulse width is the same but the rpm is 8000 rpm then duty cycle = 8000 x 13.77 / 1200 = 92%

Or you could calculate 1200 x 100% / 13.77 = 8700 rpm = 100% duty cycle

[2x0]

Awesome info, thank you!